Wall Design Examples
| 1. H = A = 8 Ft
B = .5 (H) = .5 (8) = 4
C = 36(H) =
PSF = 36(8) = 288 PSF |
| PLF = C
[(A+B)/2] = 288 [98+4)/2] = 288(6) =
1728 PLF |
| AS = 6 ft |
| AL = PLF (AS) = 1728(6) = 10,368 LBS |
| AD = AL(2) = 10,368(2) = 20,736 LBS (Minimum
anchor design for tension) |
* Note
To acheive A.D. install above anchor to 2,000 ft. lbs of torque for three times the
diameter of the lead helix. e. 10" helix x 3 = 30" |
| Consult T.I.M. guide or fluid pressure conversion chart of
driver manufactor to calculate est. torque. Also, example assumes a multiplier of 10
is applied to torque for A.D. |
|
| 2. A = 9 FT b = .5 (9) = 4.5
C = 36 (9) = 324 PSF |
| PLF = 324 [ (9+4.5)/2] = 324(6.75) = 2187 PLF |
| AS = 6 FT. AL = 2187
(6) = 13,122 AD = 13,122(2) =
26,244 |
